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Thenumbersforprintf | 3G/4G/5G开发 2022-09-28 115 0star收藏 版权: . 保留作者信息 . 禁止商业使用 . 禁止修改作品
官方C/C++开发工程师QQ群(1090119),验证请输入您的ID。标题说明晰需求,按实际需要的功能终结~可以参照下编程思路。【程序1】标题:有1、2、3、4个数字,能构成多少个互不一样且无重复数字的三位数?都是多少?1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。构成一切的摆放后再去掉不满足条件的摆放。2.程序源代码:main(){inti,j,k;printf(\n);for(i=1;ilt;5;i++)/
以下为三重循环
/for(j=1;jlt;5;j++)for(k=1;klt;5;k++){if(i!=ki!=jj!=k)/
保证i、j、k三位互不一样
/printf(%d,%d,%d\n,i,j,k);}}。。。。。。。。
c语言程序300列(学会用c语言管理日子中的问题).doc

(Official C/C   development engineer QQ group (1090119), please enter your ID for verification. The title explains the requirements, and ends according to the actual required functions~ You can refer to the following programming ideas. [Program 1] Title: There are 1, 2, 3, and 4 numbers. How many three-digit numbers can be formed that are different from each other and have no repeating numbers? , the numbers in the one digit are 1, 2, 3, and 4. After the placement that constitutes everything, the placement that does not meet the conditions is removed. 2. Program source code: main(){inti,j,k;printf(\n);for(i=1;ilt;5;i  )/
The following is a triple loop
/for(j=1;jlt;5;j  )for(k=1;klt;5;k  ){if(i!=ki!=jj!=k)/
Make sure that i, j, and k are different from each other
/printf(


n,i,j,k);}}. . . . . . . .
C language program 300 columns (learn to use c language to manage problems in life).doc)

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