1. <div>假设我有以下结构：</div><div>
   
2. </div><div>t = [['I will','take','care'],['I know','what','to','do']]</div><div>
   
3. </div><div>正如您在第一个列表中看到的，我有 'I will' 并希望它们分成两个元素 'I' 和 'will' ，结果是：</div><div>
   
4. </div><div>[['I', 'will', 'take', 'care'], ['I', 'know', 'what', 'to', 'do']]</div><div>
   
5. </div>快速脏算法如下：new = []
   
6. 
   
7. 
   
8. for sent in t:
   
9.   new = []
   
10.   for word in sent:
    
11.     temp = word.split(' ')
    
12.     for item2 in temp:
    
13.       new.append(item2)
    
14. 
    
15. 
    
16.   train_text_new.append(new)

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但我想知道是否有更易读、更有效的算法来解决这个问题。

回答
您可以制作一个简单的生成器来生成拆分，然后在列表推导中使用它：

1. t = [['I will','take','care'],['I know','what','to','do']]
   
2. 
   
3. def splitWords(l):
   
4.     for words in l:
   
5.         yield from words.split()
   
6. 
   
7. [list(splitWords(sublist)) for sublist in t]
   
8. # [['I', 'will', 'take', 'care'], ['I', 'know', 'what', 'you', 'to', 'do']]

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1. <div>假设我有以下结构：</div><div>
   
2. </div><div>t = [['I will','take','care'],['I know','what','to','do']]</div><div>
   
3. </div><div>正如您在第一个列表中看到的，我有 'I will' 并希望它们分成两个元素 'I' 和 'will' ，结果是：</div><div>
   
4. </div><div>[['I', 'will', 'take', 'care'], ['I', 'know', 'what', 'to', 'do']]</div><div>
   
5. </div>快速脏算法如下：new = []
   
6. 
   
7. 
   
8. for sent in t:
   
9.   new = []
   
10.   for word in sent:
    
11.     temp = word.split(' ')
    
12.     for item2 in temp:
    
13.       new.append(item2)
    
14. 
    
15. 
    
16.   train_text_new.append(new)

复制代码

但我想知道是否有更易读、更有效的算法来解决这个问题。

回答
您可以制作一个简单的生成器来生成拆分，然后在列表推导中使用它：

1. t = [['I will','take','care'],['I know','what','to','do']]
   
2. 
   
3. def splitWords(l):
   
4.     for words in l:
   
5.         yield from words.split()
   
6. 
   
7. [list(splitWords(sublist)) for sublist in t]
   
8. # [['I', 'will', 'take', 'care'], ['I', 'know', 'what', 'you', 'to', 'do']]

复制代码