C语言经典算法100例
官方C/C++开发工程师QQ群(1090119),验证请输入您的ID。包括100个实例代码,很好理解,如下格式,请大家下载~【程序1】标题:有1、2、3、4个数字,能构成多少个互不一样且无重复数字的三位数?都是多少?1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。构成一切的摆放后再去掉不满足条件的摆放。2.程序源代码:main(){inti,j,k;printf(\n);for(i=1;ilt;5;i++)/以下为三重循环
/for(j=1;jlt;5;j++)for(k=1;klt;5;k++){if(i!=ki!=jj!=k)/
确保i、j、k三位互不一样
/printf(%d,%d,%d\n,i,j,k);}}本资料共包括以下附件:
C语言经典算法100例.doc
(Official C/C development engineer QQ group (1090119), please enter your ID for verification. It includes 100 example codes, which are easy to understand. Please download in the following format~ Title: With 1, 2, 3, and 4 numbers, how many three-digit numbers can be formed that are different from each other and have no repeating numbers? How much are they? 1. Program analysis: The numbers that can be filled in the hundreds, tens, and ones are 1, 2, 3, and 4. After the placement that constitutes everything, the placement that does not meet the conditions is removed. 2. Program source code: main(){inti,j,k;printf(\n);for(i=1;ilt;5;i)/
The following is a triple loop
/for(j=1;jlt;5;j)for(k=1;klt;5;k){if(i!=ki!=jj!=k)/
Make sure that i, j, and k are different from each other
/printf(
n,i,j,k);}}This document includes the following attachments:
100 Examples of Classical Algorithms in C Language.doc)
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